Bansh-eman Posted November 19, 2007 Report Posted November 19, 2007 ok guys if you understand how to do this problem please post and show how u got it. the ^ shows an exponant so ^ 6x-5 is the exponant of 125 5^x x 125^6x-5 Quote
LiftdT4R Posted November 19, 2007 Report Posted November 19, 2007 Shouldnt it be 5^x * 125^(6x-5) or 5^x = 125^(6x-5)? It's hard to tell the way it's typed. Quote
LiftdT4R Posted November 19, 2007 Report Posted November 19, 2007 I'm guessing it is 5^x * 125^(6x-5) = some number. So if you want to simplify it, apply the natural log to both sides, and on the left you will get (19-x)*ln(5), by the ln rules for addition and multiplication. Quote
ohiobanshee Posted November 19, 2007 Report Posted November 19, 2007 math is for losers Spoken like one Quote
LiftdT4R Posted November 19, 2007 Report Posted November 19, 2007 You can't blame him, he's from New Jersey. :yelrotflmao: Quote
Michael Jackson Posted November 19, 2007 Report Posted November 19, 2007 You can't blame him, he's from New Jersey. :yelrotflmao: if im not mistaken it says your from central joisey? and i was only jokin, math is for winners! Quote
zach45 Posted November 19, 2007 Report Posted November 19, 2007 not just winners.... big winners Quote
Bansh-eman Posted November 19, 2007 Author Report Posted November 19, 2007 final is complete! DONE WITH MATH!!!! Quote
dajogejr Posted November 19, 2007 Report Posted November 19, 2007 math is for losers That's only because 7+7 = Date Night + probation ya pedophile. Quote
LiftdT4R Posted November 19, 2007 Report Posted November 19, 2007 if im not mistaken it says your from central joisey? and i was only jokin, math is for winners! Hence the roller... Quote
FireHead Posted November 29, 2007 Report Posted November 29, 2007 I'm guessing it is 5^x * 125^(6x-5) = some number. So if you want to simplify it, apply the natural log to both sides, and on the left you will get (19-x)*ln(5), by the ln rules for addition and multiplication. You have to give it the natural log......... :biggrin: Quote
Lepew Posted November 29, 2007 Report Posted November 29, 2007 (edited) If I was given the problem he first stated I could only say f(x) is equal to some positive number. If you gave me what the equation was equal to, I could tell you what x was , by yes, using a log function on both sides and solving for x. It threw me where he dosen't equal the equation to something. Out of habit I tried to equal it to 0 and realized I was going down the wrong path. Edited November 29, 2007 by Lepew Quote
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