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let my buddy borrow my banshee


jack vo

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Seriously, be happy he even added oil, let alone too much. 

Lets do some math! So, 20:1 means 20 parts gasoline to 1 part oil, 20+1=21 total parts. 40:1 means 40 parts gasoline to 1 parts oil, 40+1= 41 total parts. Take 1/41 to get 2.44% oil and 1/21 to get 4.76% oil. So 4.76%-2.44%=2.32%.  So he added 2.32% too much oil. This effectively leaned your jetting by 2.32% due to the displacement of the fuel by the oil.  I very much doubt a 2.32% change in your jetting is going to do anything unless your jetting was very lean to begin with.

 

Edit: "So he added 2.32% too much oil" is incorrect. He added 100% too much oil. It should have said, "The fuel contained 2.32% too much oil"

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Seriously, be happy he even added oil, let alone too much. 

Lets do some math! So, 20:1 means 20 parts gasoline to 1 part oil, 20+1=21 total parts. 40:1 means 40 parts gasoline to 1 parts oil, 40+1= 41 total parts. Take 1/41 to get 2.44% oil and 1/21 to get 4.76% oil. So 4.76%-2.44%=2.32%.  So he added 2.32% too much oil. This effectively leaned your jetting by 2.32% due to the displacement of the fuel by the oil.  I very much doubt a 2.32% change in your jetting is going to do anything unless your jetting was very lean to begin with.

This is completely wrong. He doubled the amount of oil he was told to use. He used 32 oz instead of 16 oz to the same amount of fuel.

 

His Motor will be fine but your math needs some serious help. Lol!

 

 

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5 hours ago, spurdy said:

This is completely wrong. He doubled the amount of oil he was told to use. He used 32 oz instead of 16 oz to the same amount of fuel.

 

His Motor will be fine but your math needs some serious help. Lol!

 

 

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32/(640+32)=0.0476   16/(640+16)=0.0244

0.0476-0.0244=0.0232

Maybe I am doing something wrong. Please correct me.

 

Edit:  I just realized that my math only works if you ADD the oil to 5 gallons of fuel. ie Final volume equals 5 gallons plus the amount of oil added

If you put your oil in the jug first then add fuel to the 5 gallon line ( final volume being 5 gallons (640 oz) including the oil) then you are making a 5% (19:1 or 608 oz fuel to 32oz oil ) and a 2.5% (39:1 or 624 oz fuel to 16 oz oil) solution. Then he would have only added 2.5% too much oil.

v/v%=(volume solute/(volume solvent+volume solute))x100%  so (oil/(gas+oil))x100% = volume% oil

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